0=x^2-10x-56

Solution for 0=x^2-10x-56 equation:

0=x^2-10x-56

We move all terms to the left:

0-(x^2-10x-56)=0

We add all the numbers together, and all the variables

-(x^2-10x-56)=0

We get rid of parentheses

-x^2+10x+56=0

We add all the numbers together, and all the variables

-1x^2+10x+56=0

a = -1; b = 10; c = +56;
Δ = b2-4ac
Δ = 102-4·(-1)·56
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-18}{2*-1}=\frac{-28}{-2}
=+14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+18}{2*-1}=\frac{8}{-2}
=-4
$